the difference between the squares of two consecutive numbers is 31 find the number
nandan83:
fast
Answers
Answered by
0
let the two consecutive no are x and x+1
A.T.Q
(x+1)^2-x^2=31
x^2+1+2x-x^2=31
2x+1=31
2x=30
x=15
therefor one no. is 15 and other is 16 hope this is helpful
A.T.Q
(x+1)^2-x^2=31
x^2+1+2x-x^2=31
2x+1=31
2x=30
x=15
therefor one no. is 15 and other is 16 hope this is helpful
Similar questions