Question

The difference between the squares of two positive integers is 2009. What is the maximum possible difference between these two integers?

Answer 1

Answer:

41

Step-by-step explanation:

Let the two positive integers be x and y.

x^2-y^2=2009.

Hence x=45,y=4.

45^2=2025.

4^2=16.

Therefore, 45-4=41