the difference between the sum of squares of first n natural numbers in the sum of first n natural numbers is always divisible by 2
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Step-by-step explanation:
n = 3
Squares of first three numbers
= 3x3 + 2x2 + 1x1
= 9 + 4 + 1
= 14
Squares of sum of first three numbers
= (3 + 2 + 1)x(3 + 2 + 1)
= 6x6
= 36
Difference
= 36 - 14
= 22
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