Question

The difference between the two sisters is 5years. 10 years ago, if the elder one was twice as old as younger one, find their present ages.

Answer 1

dIff 5years

small sIster 10 years ago age=x

big sistea age before 10 year=2x

the diff never changes.

therefore,2x-x=5

x=5

therefore the ages of the sisters are

10+10 & 5+10

=20 & 15 Respectively.

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that the difference between the two sisters is $5$years. $10$ years ago, if the elder one was twice as old as younger one

To Find:-

We have to find that their present ages.

Solution:-

According to the problem

The ages of two sisters is $x$ and $y$ respectively

From First condition,

$x-y=5....(1)$

$10$ years ago.

$x=2 y...(2)$

substituting $x=2 y$ in equation. $(1)$

$\therefore 2 y-y=5$

$&\therefore 2 y-y=5 \\&\therefore y=5$

Final Answer:-

The younger sister age is $15$ and elder's sister's age is $20$.

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