the difference between two acute angle of a right angle triangle is π/9 find the angle in degrees
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let two acute angles be x and y
the difference between two acute angle of a right angle triangle is π/9
so, x - y = π/9
where π = 180°
x - y = 180°/9
x - y = 20°
x = y + 20°..............(1)
sum of two acute angle is 90
so, x + y = 90°.........(2)
substitute (1) in (2)
y + 20° + y = 90°
2y = 90° - 20°
2y = 70°
y = 70°/2
y = 35°
substitute y in (1)
x = 35° + 20°
x = 55°
so, two acute angles are x = 55° and y = 35°
the difference between two acute angle of a right angle triangle is π/9
so, x - y = π/9
where π = 180°
x - y = 180°/9
x - y = 20°
x = y + 20°..............(1)
sum of two acute angle is 90
so, x + y = 90°.........(2)
substitute (1) in (2)
y + 20° + y = 90°
2y = 90° - 20°
2y = 70°
y = 70°/2
y = 35°
substitute y in (1)
x = 35° + 20°
x = 55°
so, two acute angles are x = 55° and y = 35°
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