Question

the difference between two acute angles of a right angled triangle is 7π/30 find the angles of the triangle in degree​

Answer 1

Answer:

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Step-by-step explanation:

so for a right angled triangle let its remaining two acute angles be x and y degrees respectively

so here x-y=7pi/30

so 7pi/30=7×180/30

=7×6=42 degrees

thus then x=y+42 (1)

now applying angle sum property on this triangle

we get

x+y+90=180

ie x+y=90

so y+y+42=90 from (1)

ie 2y=48

ie y=24 degrees

substitute value of y in (1)

we get

x=66 degrees

hence the remaining angles of triangle are 66 degree and 24 degrees respectively

Answer 2

Answer:

let x, y are two acute angel .

=>x+y = pi/2 (90 degree)

Given, x-y = 7pi/30

(pi=180 degree which is 3.141 radian)

So equating both equation we get, 2x = 11pi/15

x = (11×180)/30 =66degree

=> y= 24 degree

So two angels are 66degree & 24 degree