Question

the difference between two natural no. is 73. if the greater no. is divided by smaller no. .the quotient is 4 and reminder is 4. then find the numbers

Answer 1

Answer:

The numbers are 96 & 23

Step-by-step explanation:

Given:

1. Difference between two natural numbers = 73
2. Greater number divided by Smaller number leaves quotient 4 & remainder 4

Solution:

Let the numbers be m, n where m is the greater one

According to given 1, we get

m - n = 73 ( Eq 1 )

According to given 2, we get

• Dividend = m
• Divisor = n
• Quotient = 4
• Remainder = 4

$dividend \: = (divisor \times quotient) + remainder$

=> m = n(4) + 4

=> m = 4n + 4 ( Eq 2 )

Subtracting Eq 1 from Eq 2, we get

=> m - ( m - n ) = 4n + 4 - 73

=> m - m + n = 4n - 69

=> n = 4n - 69

=> 3n = 69

=> n = 23

Putting n = 1 in Eq 1, we get

m - 23 = 73

=> m = 73 + 23

=> m = 96