Question

the difference between two number is 16 and one number is twice the other find theml​

Answer 1

Answer:

Let the two numbers be, larger x and smaller y

The sum of two numbers is 16

x + y = 16…Eq..1

their difference is 2.

x - y = 2

x = 2 + y….Eq..2

Now putting the value of x from Eq..2 to Eq..1

x + y = 16

2 + y + y = 16

2 + 2y = 16

2y = 16 - 2

2y = 14

y = 14/2

y = 7

Thus one number is 7. Now finding other numberby substituting the value of y in Eq..1

x = 2 + y

x = 2 + 7

x = 9

The other number is 9

The two numbers are 7 and 9

Now the product of two numbers

7 × 9 = 63

The product of two numbers is 63

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Answer 2

Answer:

Answer:

Step-by-step explanation:

Given :-

The difference between the two numbers is 26.

One number is 3 times the other

To Find :-

The Numbers.

Solution :-

Let the larger number be x and the smaller number be y.

According to the Question

1st Equation

x –y = 26 ………….(i)  

2nd Equation

x = 3y …………(ii)  

Putting x value in Eq (i)

⇒ x –y = 26

⇒ 3y –y = 26  

⇒ 2y = 26  

⇒ y = 26/2

⇒ y = 13  

Putting y value in Eq (i)

⇒ x –y = 26  

⇒ x – 13 = 26  

⇒ x = 26 + 13

⇒ x = 39  

Hence, the required numbers are 39 and 13.

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