Question

The difference between two numbers is 11 and the product of the numbers is 2420. Find the sum of the numbers.

Answer 1

Step-by-step explanation:

Let term be:

a−2d,a−d,a,a+d,a+2d

given sum of these terms is 25

∴a−2d+a−d+a+a+d+a+2d=25

5a=25

a=5

Also product =2520

⇒(a−2d)(a+2d)(a−d)(a+d).a=2520

(a

2

−4d

2

)(a

2

−d

2

)a=2520

(25−4d

2

)(25−d

2

)=504

4d

4

−125d

2

+121=0

(d

2

−1)(4d

2

−121)=0

d=±1

or

d=±

2

11

↓

it will not give −

2

1

value of any terms.

So we will consider

d=±

2

11

So largest term is

5+2×

2

11

=16

same method follow . the numbers are different mark me as brainliest and redmi 5 points then I will answer to the same question with same numbers with hand written