Question

The difference between two numbers is 18. IF
four times the second number is less than three
times the first number by 18, what is the sum of
these two numbers?​

Answer 1

Answer is :-90

Let first no be x and second no be y

ATQ

x-y=18........(i)

And 3x-4y=18....(ii)

On multiplying eq(i) by 3 and then subtracting from eq(ii) we get

3x-3y=54

3x-4y=18

Y=36 so x=90

Answer 2

Answer:

Step-by-step explanation:

Let the first number be x.

Second number = x - 18

According to Question,

4(x - 18) + 18 = 3x

4x - 72 + 18 = 3x

4x - 54 = 3x

4x - 3x = 54

x = 54

Hence, first number = 54

Second number = 54 - 18 = 36

Thus, sum = 54 + 36 = 90