the difference between two numbers is 26 and one number is three times the other find them
52 and 78
therefore we will multiply 26×3=78then it is 78minus52=26
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B1, B2 and B3 are three identical bulbs connected as shown in the figure. When all the three bulbs glow, a current of 3A is recorded by ammeter A. (a). What happens to the glow of other bulbs when B1 gets fused? (b). What happens to the reading of A1, A2, A3 and A when B2 gets fused? (c). How much power is dissipated in the circuit when all the three bulbs glow together ?