the difference between two numbers is 3 and the difference of their square is 69 find the number
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I hope this will help you.
let two no. be x and y
x-y=3. 1equation
x²-y²=69
(x+y)(x-y)=69
x+y=69/x-y
x+y =69/3
x+y=23. 2 equation
adding both equation
x-y=3
x+y=69
2x=72
x=36
put the value of x in 1 equation
x-y=3
36-3=y
33=y
then no. be 36 and 33
let two no. be x and y
x-y=3. 1equation
x²-y²=69
(x+y)(x-y)=69
x+y=69/x-y
x+y =69/3
x+y=23. 2 equation
adding both equation
x-y=3
x+y=69
2x=72
x=36
put the value of x in 1 equation
x-y=3
36-3=y
33=y
then no. be 36 and 33
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