The difference between two numbers is 40 if the smaller number is divided by the larger number the fraction obtained is 6 divided by 11 find the number plzz give full explanation
Answers
Answered by
3
Answer:
x = 88
y = 48
Step-by-step explanation:
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Answered by
0
Answer:
Smaller number = 48
Larger number = 98
Step-by-step explanation:
Let the two numbers be x & y.
According to the first condition,
x - y = 40
x = 40 + y eq 1
According to the second condition,
y/x = 6/11
On cross multiplying,
11y = 6x
6x - 11y = 0 eq 2
Substituing the value of 'x' in eq 2,
6(40 + y) - 11y = 0
240 + 6y - 11y = 0
240 - 5y = 0
240 = 5y
240/5 = y
Or, y = 48
x = 40 + y
x = 40 + 48
x = 98
Thus, the two numbers are 48 & 98.
Smaller number = 48
Larger number = 98
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