Question

The difference between two numbers is 642.when the greater number is divided by the smaller, the quotient is 8 and the remainder is 19. Find the smaller number.

Answer 1

let those two numbers be x and y

x - y = 642
x = 642 + y ......(1)
and x will be greater number as 642 is positive
( in subtraction)

so x ÷ y is giving you quotient as 8 and
remainder as 19

so we can say that ( y × 8 )+ 19 = x
8y = x - 19

from (1)
8y = 642 + y - 19
8y - y = 623
7y = 623
y = 623 / 7
y = 89

using (1)
x = 642 + 89
x = 731

hope this helps you

Answer 2

Answer:

89

Step-by-step explanation:

Let the two number be x and y such that x>y

Now we are given that The difference between two numbers is 642.

So, $x-y=642$

$x=642+y$  ---1

Now we are given that When the greater number is divided by the smaller, the quotient is 8 and the remainder is 19.

Divisor = y

Dividend = x

Quotient = 8

Remainder = 19

$Dividend=(Divisor \times Quotient)+Remainder$

$x=(y \times 8)+19$

Using 1

$642+y=8y+19$

$642-19=8y-y$

$623=7y$

$\frac{623}{7}=y$

$89=y$

Hence the smaller number is 89