Math, asked by tirtha1, 1 year ago

the difference between two numbers is 7 six times the smaller plus the larger is 77 find the numbers


shubham960: the smaller number is 10 and the larger number is 17
tirtha1: how
Divyanshu101: Please can you explain how you found out the answer
Divyanshu101: I cant figure it out
shubham960: 6 time of the 10 is 60 and 60+17=77 and difference between them i.e 17-10 is also 7 which satisfies the condition
Divyanshu101: ok
rehmanvaheedur7: No problem

Answers

Answered by rehmanvaheedur7
1
10 &17 are the numbers
Answered by Anonymous
34

\huge\underline\mathrm{SOLUTION:-}

AnswEr:

  • \large{\underline{\boxed{\mathfrak\blue{Two \: numbers = 10 \: \& \: 17 }}}}

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

Let the larger number be a & smaller number be b.

1st case:

⇒ a - b = 7

⇒ a = b + 7 .................(eq.1)

2nd case:

⇒ 6b + a = 77

Putting value of a from (eq.1):

\sf {\: \: \: \: \:\: [\because a = b + 7]}

⇒ 6b + b + 7 = 77

⇒ 7b + 7 = 77

⇒ 7b = 77 - 7

⇒ 7b = 70

⇒ b = 70/7

⇒ b = 10

\therefore{\underline{\boxed{\rm{Smaller \: number = 10}}}}

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

Putting value of b in (eq.1):

⇒ a = 10 + 7

⇒ a = 17

\therefore{\underline{\boxed{\rm{Larger \: number = 17}}}}

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

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