the difference between two positive integers is 36 the quotient,when one integer is divided by other is 4 find two integer
singh171:
answer is 12 and 48
x-y=36 andx/y=4 then, x=36+y...(1) and x=4y now put the value of x in =equation (1) we get. 4y=36+y=3y=36 y=12 again put this value in equation( 1
we get x=48 now answer is 12 and 48
Answers
Answered by
125
Hey!!!
________
let the two positive integers be x and y
Then ATQ,
=> x - y = 36
=> x = 36 + y --------(1)
Also
=> x/y = 4
=> x = 4y
Using (1) in above equation
=> 36 + y = 4y
=> 3y = 36
=> y = 12
Using y in (1)
=> x = 36 + 12
=> x = 48
Thus the two integers are 12 and 48
_________
Hope this helps ✌️
________
let the two positive integers be x and y
Then ATQ,
=> x - y = 36
=> x = 36 + y --------(1)
Also
=> x/y = 4
=> x = 4y
Using (1) in above equation
=> 36 + y = 4y
=> 3y = 36
=> y = 12
Using y in (1)
=> x = 36 + 12
=> x = 48
Thus the two integers are 12 and 48
_________
Hope this helps ✌️
(:
Oo
Wait... Someone will give
Till then.. Gn
Correct it bro
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ryt
correct
Answered by
103
Hey!
_____________
A.T.Q
Let one integer be x and another be y
x - y = 36
x = 36 + y ------ (i)
And,
x / y = 4
x = 4y --------- (ii)
Combining (i) and (ii)
36 + y = 4y
36 = 4y - y
36 = 3y
y = 36/3
y = 12
Putting value of y in (i)
x = 36 + 12
x = 48
_____________
Hope it helps...!!!
_____________
A.T.Q
Let one integer be x and another be y
x - y = 36
x = 36 + y ------ (i)
And,
x / y = 4
x = 4y --------- (ii)
Combining (i) and (ii)
36 + y = 4y
36 = 4y - y
36 = 3y
y = 36/3
y = 12
Putting value of y in (i)
x = 36 + 12
x = 48
_____________
Hope it helps...!!!
hii nikkki
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^_^
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