The difference between two positive numbers is 4 and the difference between their cubes is 316 . Find: 1 their product2 the sum of their squares
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a-b=4
a^3-b^3=316
(a-b)^3=a^3-b^3-3ab(a-b)
64=316-12ab
252=12ab
ab=21
a^3-b^3=316
(a-b)^3=a^3-b^3-3ab(a-b)
64=316-12ab
252=12ab
ab=21
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