The difference bt outside Nd inside radi of a metallic cylinder pipe of length 14cm is 2cm if the pipe is made of 440 cm find the outer Nd inner radius of the pipe
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Let r be inner radius and R be outer radius
Volume of pipe = Area of cross section ×height
= π(R^2 - r^2)× h=440
= (22/7)(R+r)(R-r)×14=440
= R+r=5 and. R-r=2
R = 3.5
r = 1.5
Volume of pipe = Area of cross section ×height
= π(R^2 - r^2)× h=440
= (22/7)(R+r)(R-r)×14=440
= R+r=5 and. R-r=2
R = 3.5
r = 1.5
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