. The difference in lengths of two adjacent sides of the right angle of a right-angled tri- angle is 1 cm. If the area of the triangle is 210 cm”, find the length of its hypotenuse
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Let x cm be the one of the sides, then (x−7) cm be another side.
Area of triangle =60cm
2
(given)
We know, Area of triangle =
2
1
(Base×height)
⇒60=
2
1×x×(x−7)
⇒120=x
2
−7x
or x 2
−7x−120=0
Solving above equation, we have
(x−15)(x+8)=0
x=15 or x=−8
Since length measure cannot be negative, so neglect x=−8
One side =15cm
Another Side =x−7=15−7=8cm
Apply Pythagoras theorem:
Hypotenuse 2 = BasePerpendicular 2Hypotenuse
2 = (15 2+8 2 )
Hypotenuse = 289 =17
Therefore,
perimeter of triangle = Sum of all the sides =(15+8+17)cm=40cm
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