Question

the difference of 2 no. is 5 & the difference of their reciprocals is 1/10?find the no.????

Answer 1

HEYA!!!!!!

YOUR SOLUTION

THE DIFFERENCE IS= 5

LET THE NUMBER BE X AND Y.

THEN , X-Y =5 -----------eq.(I)

DIFFERENCE OF THE RECIPROCAL = 1/10

THEN, 1/X - 1/Y = 1/10
-0
Y-X/XY = 1/10

10Y- 10X = XY

-10X + 10Y = XY

-10( X- Y) = XY

-10 (5) = XY

-50 = XY

Y = -50/X

FROM EQUATION 1 ,

X + 50/X = 5

$x {}^{2} - 5x + 50 = 0$
NOW U CAN SOLVE IT BY QUADRATIC FORMULA :--

$- b + - \sqrt{b {}^{2} - 4 \times ac \ } \div 2a$

HOPE IT HELPS.....M

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