The difference of square of 2 natural number is 45.The square of smaller number is 4 times larger number.Find the number.
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from the given information
x^2 - y^2 = 45
when, x>y
then according to formula we get ,
y = (4x)^(1/2)
then , x^2 - 4x - 45 =0
by factorizing we get ,
(x-9)(x-5)=0
ie. x=9 or x=5
when x=9 then y= 6
when x=5 then y=(20)^(1/2) or 2*(5)^(1/2)
:p
x^2 - y^2 = 45
when, x>y
then according to formula we get ,
y = (4x)^(1/2)
then , x^2 - 4x - 45 =0
by factorizing we get ,
(x-9)(x-5)=0
ie. x=9 or x=5
when x=9 then y= 6
when x=5 then y=(20)^(1/2) or 2*(5)^(1/2)
:p
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