The difference of the square of two number is 45 the square of the smaller is 4 times the larger number. find the number.
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from the given information
x^2-y^2=45
when x>y
then y=(4x)^(1/2)
ie. x^2 -4x-45=0
factorizing we get ,
(x-9)(x-5)=0
x=9 or x=5
when x=9 then y=6
when x=5 then y=(20)^(1/2) or 2*(5)^(1/2)
:p
x^2-y^2=45
when x>y
then y=(4x)^(1/2)
ie. x^2 -4x-45=0
factorizing we get ,
(x-9)(x-5)=0
x=9 or x=5
when x=9 then y=6
when x=5 then y=(20)^(1/2) or 2*(5)^(1/2)
:p
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