the difference of squares of two consective natural numbers is 2011
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let one consecutive no. be x, and the other no. be (x+1)
(x+1)^2 -x^2=2011
now solve it.
hope this helps
(x+1)^2 -x^2=2011
now solve it.
hope this helps
Answered by
2
@
let two number be x , x+1
(x+1)²-x² = 2011
=> x² + 1 + 2x - x² = 2011
=> 2x = 2010
=> x = 1005
@:-)
let two number be x , x+1
(x+1)²-x² = 2011
=> x² + 1 + 2x - x² = 2011
=> 2x = 2010
=> x = 1005
@:-)
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