The difference of squares of two consecutive even natural numbers is 12. Taking p as the smaller of two numbers, form an equation in p and hence find the larger of the two.
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Answered by
1
Answer:
The numbers are 2 and 4
Step-by-step explanation:
Let the two consecutive even natural numbers be p and p+2
Given, that (p+2)² - p² = 12
⇒ p² + 4p + 4 - p² = 12
⇒ 4p + 4 = 12
⇒ 4p = 12 - 4
⇒ 4p = 8
⇒ p = 8/4
⇒ p = 2
p + 2 = 2 + 2 = 4
So, the numbers are 2 and 4
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Answered by
0
Answer :
2 , 4 [4 2 - 2 2 = 16 - 4 = 12]
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