The difference of squares of two numbers is 180 the square of the smaller number is 8 times the large no.find the two noumber
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let large number is x
so it's square is x^2
let small number is y
so it's square is y^2
now according to given condition ,
x-2 - y^2 = 180
but , y^2 = 8x
so , x-2 - 8x - 180 = 0
x-2 - 18x + 10x - 180 = 0
x ( x - 18 ) +10 ( x - 18 ) = 0
(x - 18 ) ( x + 10 ) = 0
(x - 18 ) = 0 or ( x + 10 ) = 0
x = 18 or x = -10
but x = - 10 is not possible
so x = 18
I.e. larger number is 18
so smaller is , y^2 = 8 × 18
y^2 = 144
y = 12
so it's square is x^2
let small number is y
so it's square is y^2
now according to given condition ,
x-2 - y^2 = 180
but , y^2 = 8x
so , x-2 - 8x - 180 = 0
x-2 - 18x + 10x - 180 = 0
x ( x - 18 ) +10 ( x - 18 ) = 0
(x - 18 ) ( x + 10 ) = 0
(x - 18 ) = 0 or ( x + 10 ) = 0
x = 18 or x = -10
but x = - 10 is not possible
so x = 18
I.e. larger number is 18
so smaller is , y^2 = 8 × 18
y^2 = 144
y = 12
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