The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find the two numbers.
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Answer:
x^2-y^2=180
y^2=8x
x^2-8x-180=0
x^2-18x+10x-180=0
x(x-18)+10(x-18)=0
(x-18)(x+10)=0
x=18;-10
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Step-by-step explanation:
Let the large number is =x
Square of smaller number is =8x
Now, According to given question,
x²−8x=180
⇒x²−8x−180=0
⇒x²−(18−10)x−180=0
⇒x²−18x+10x−180=0
⇒x(x−18)+10(x−18)=0
⇒(x−18)(x+10)=0
⇒x−18=0,x+10=0
⇒x=18,x=−10
⇒x=−10,18
Either
x=−10 and x=18(x can't be negative)
x=18 is true (Positive value)
Now, square of small number
=18x=18×8=144
√144
=12
Hence, the answer is 12
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