Question

the difference of the compound interest of second year and the first year on rupees 4000 at 10% is rupees.......
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Answer 1

Principal(P) = Rs 4000

Rate of Interest(r ) = 10%

Time = 2.5 years Here first we take n = 2 years.

A = P( 1 + r /100)n Where A = Amount and n = number of years

A = 4000 (11/10)2

A = 4000 ( 121 / 100 )

A = Rs 4840

The Amount after two years = Rs 4840 Now Principal = Rs 4840

Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242

Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082

C.I = A - P

C.I = Rs 5082 - Rs 4000 = Rs1082

∴ The compound interest is Rs 1082

2.5years is miss