The difference of the digits of a two digit number is 2. The sum of the number and the number obtained by reversing the digits is 66. Find the number
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Let the number be xy
A.t.g.c
Xy+yx=66
10x+y+10y+10x=66
11x+11y=66
X+y=6.........1
And
Also x-y=2........2
Adding 1 and 2 we get
X=4
Put x =4 In eq. 1
4+y=6
Y=2
Therfore number is 42 or 24
A.t.g.c
Xy+yx=66
10x+y+10y+10x=66
11x+11y=66
X+y=6.........1
And
Also x-y=2........2
Adding 1 and 2 we get
X=4
Put x =4 In eq. 1
4+y=6
Y=2
Therfore number is 42 or 24
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