The difference of the squares of 2 number is 45 the square of smaller number is 4 times longer number. find the number
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Answer:
a=9;b=6
Step-by-step explanation:
given a²-b² = 45
if b is taken as the smaller no.
then given b² = 4a
=> a² - 4a = 45
=> a² - 4a - 45 =0
=> a² - 9a + 5a - 45 = 0
=> a(a-9) - 5(a-9) = 0
=> (a-9)(a-5) = 0
=> a-9 = 0 => a=9 => b= √(4*9) = √36 = 6 => b=6
=> a-5 = 0 => a=5 => b= √(4*5) = √20 (not suitable)
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