Question

The difference of the squares of two
consecutive odd integer is divisible by
which of the following integers?​

Answer 1

Answer:

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Answer 2

Answer:

Solution 1

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Let two odd numbers be (2n - 1) and (2n + 1)

Difference between the squares

= (2n + 1)2 - (2n - 1)2

= [4n2 + 4n + 1] - [4n2 - 4n + 1]

= 8n which is always divisible by 8

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Solution 2

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Take any two odd numbers, say 1 and 3

Difference between the squares = 32 - 12 = 9 - 1 = 8

From the given choices, now you can easily figure out the answer as 8