Question

The difference of the squares of two numbers is 45 the square of the smaller number are 4 times larger number find the number

Answer 1

Let the smaller number be X

Larger number= Y

ATQ,

y^2-x^2= 45

x^2= 4 y

Putting the value of x^2 in the first equation

y^2-4y= 45

y^2-4y-45=0

y^2-9y+4y-45=0

y(y-9)+4(y-9)=0

(y-9)(y+4)=0

y=9 and (-4)

If y=9

Then x=4

If y=(-4)

Then x=(-9)