Question

. The difference of the squares of two positive numbers is 145. The square of smaller number is 8 more than 8 times the larger number. Find the numbers.

Answer 1

Step-by-step explanation:

Let one no.be x and other be y(smaller no.).

Then,x^2-y^2=145(given) (i)

Also,y^2=8x+8(given) (ii)

Put the value of y^2 in (i)

x^2-(8x+8)=145

x^2-8x-8-145=0

x^2-8x-153=0

(x+9)( x-17)=0

Since the no.s are positive,x=17

y^2=8x+8=8(17)+8=144

y=12

So the no.s are 12 and 17.

Answer 2

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