The difference of two natural numbers be 5and thd sum of its square be 97.find the numbers
Answers
Answered by
1
Answer:9 and 4
Step-by-step explanation:
Let the two nos ne X and y
x-y=5
x=5+y
(x)²+(y)²=97
substituting value of X
(5+y)²+(y)²=97
25+10y+y²+y²=97
2y²+10y-72
divide by 2
y²+5y -36=0
y²+9y-4y-36=0
y(y+9)-4(y+9)=0
y=4 or y=-9
since its natural no.
therefore we discard -9
therefore 4+5=9
therefore the nos are 9 and 4
Similar questions
Math,
5 months ago
English,
5 months ago
Environmental Sciences,
11 months ago
Physics,
1 year ago
Science,
1 year ago