Question

the difference of two no. is 3 and the difference of their square is 69 .Find the no.

Answer 1

let a,b are the two numbers
then a>b
a-b =3
a=3+b -------•eqn 1
a^2-b^2 =69
(a-b)(a+b)=69
3 (a+b)=69
a+b =23-------•eqn 2
substitute 1 in 2
3+b+b = 23
2b =20
b = 10
substitute b value in eqn 1
a=3+10
a=13

Answer 2

hey dear


here is your answer


_________________________________


Let the number be x and y


according to question difference is 3


So,

x - y =3

x = 3 + y


Now we get two number as ( y ) and ( y + 3 )




Also difference of their square is 69




That is x^2 - y ^2 = 69



But x = y + 3



So, ( y + 3 ) ^2 ( - y ) ^2 = 69


y^2 + 3^2 +2 ( 3 ) ( y ) - y^2 = 69



9 + 6 y = 69


6y = 69 - 9


6y = 60

y = 60 / 6


y = 10


second number x = y + 3 = 10 + 3 = 13



hence answer is 10 , 13

__________________________________



hope it helps


thank you