what is remainder when n^2+13n+2 is divided by (3n+5)
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let p(n)= n²+13n+2
p(-5/3)=(-5/3)²+13(-5/3)+2. [as 3n+5=0]
= 25/9-65/3+2.
= -152/9
the remainder is -152/9
p(-5/3)=(-5/3)²+13(-5/3)+2. [as 3n+5=0]
= 25/9-65/3+2.
= -152/9
the remainder is -152/9
Prajju111:
can you find the value in any other way? because we can't know the n value in all cases right?
yes we can...this method is also known as remainder theorem...
other method can be long division method
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