Question

the difference of two numbers is 14 and their sum is 40.find out the product of the numbers​

Answer 1

Answer:

27 and 13

Step-by-step explanation:

(x+y)+ (x-y) :40 +14

2x:54

x: 54/2 :27

Substitute it's value

we have

27 +y : 40

y: 40-27 : 13

so numbers are 27 and 13 respectively

Answer 2

Given:

• The difference of two numbers is 14.

• Their sum is 40.

To calculate:

• The product of the numbers.

Calculation:

Let,

• First number = x
• Second number = y

According to the question,

$\longrightarrow \bf \red {x - y = 14 }$

[ Since, the difference of two numbers is 14. ]

From this equation,

$\longrightarrow \sf {x = 14 +y}$ (By transposition.). . . . . . . (Equation 1)

Also,

$\longrightarrow \bf \red{x + y = 40}$

Now, from this equation we'll find the value of x and y.

$\longrightarrow \sf {(14+y) + y= 40 }$

• Substituting the value of x from equation (I).

$\longrightarrow \sf {14+y+ y= 40 }$

$\longrightarrow \sf {14+2y= 40 }$

$\longrightarrow \sf {2y= 40-14 }$

$\longrightarrow \sf {2y= 26 }$

$\longrightarrow \sf {y=\dfrac{26}{2} }$

$\longrightarrow\fbox{ \sf {y= 13 }}$

Henceforth,

• Second number (y) = 13

And,

→ First number (x) = 14 + y [ From equation 1]

→ x = 14 + 13

→ x = 27

• First number (x) = 27

~Calculating their product:

$\longrightarrow\boxed{ \sf { Product = First \: Number \times Second \: Number }}$

$\longrightarrow \sf {Product = xy }$

$\longrightarrow \sf {Product = 13 \times 27 }$

$\longrightarrow\fbox{ \sf\red {Product = 351}}$

Therefore, the product of the numbers is 351.