The difference of two numbers is 15. If the sum of three times the first number and two times the second turns out to be 90, then the sum of these two numbers would be equal to?
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Let us assume that the 2 numbers be 'x' and 'y'
It is given that,
=> x-y=15-----1 and
3x+2y=90------2
Multiply the 1st equation with 3
=> 3x-3y=45----3
Subtract eqn2 from eqn3
=>3x-3y=45
-3x-2y=-90
---------------
0-5y=-45
i.e, 5y=45
y=9
Subtitute the value of y in eqn1 to get the value of x
=> x-9=15
x=24
Therefore the sum of the 2 numbers will be
=> x+y=24+15=39
It is given that,
=> x-y=15-----1 and
3x+2y=90------2
Multiply the 1st equation with 3
=> 3x-3y=45----3
Subtract eqn2 from eqn3
=>3x-3y=45
-3x-2y=-90
---------------
0-5y=-45
i.e, 5y=45
y=9
Subtitute the value of y in eqn1 to get the value of x
=> x-9=15
x=24
Therefore the sum of the 2 numbers will be
=> x+y=24+15=39
sarah07:
Thank you but there is a slight mistake. We'll add x=24 and y=9 which will sum upto 33
oops i'm sorry
just make sure you understand the steps
Yeah i did, it was helpful. thank you so much
anytime buddy :)
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