The difference of two numbers is 3 times the
smaller number, how many times is the smaller
number contained in their sum? If the greater
is 292. find their product.
Answers
Answered by
3
let the number be a and b
and b is greater equal to 292
difference is
b-a = 3a
292 -a = 3a
4a = 292
a = 73
hence smallest number is 73
sum :-
a+b = 73+292
a+b = 365
a+b= 5×73 = 5×a
hence, 5 times is the smaller number contained in their sum.
product:-
a×b = 73×292 = (70+3)×292
=20 440+876 =21316
i hope it will be helpful for u
NeelamG:
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