the difference of two numbers is 5 and the difference of their reciprocal is1/10 find the number
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Let the two numbers b x and y
According to the question
x - y = 5
x = 5 + y
The difference of the reciprocal is 1 by 10
So 1/x - 1/y = 1/10
1/ 5+y - 1/ y = 1/10
By taking the LCM we will get
5 + y - y / y2 + 5y = 1/10
by cross multiplication we will get
50 = y2 + 5y
y2 + 5y - 50 = 0
y2 + 10y - 5y - 50 = 0
y ( y + 10 ) - 5 ( y - 10 ) = 0
( y + 10 ) ( y - 5 )
y = - 10 ( negative value is not possible)
y = 5
According to the question
x - y = 5
x = 5 + y
The difference of the reciprocal is 1 by 10
So 1/x - 1/y = 1/10
1/ 5+y - 1/ y = 1/10
By taking the LCM we will get
5 + y - y / y2 + 5y = 1/10
by cross multiplication we will get
50 = y2 + 5y
y2 + 5y - 50 = 0
y2 + 10y - 5y - 50 = 0
y ( y + 10 ) - 5 ( y - 10 ) = 0
( y + 10 ) ( y - 5 )
y = - 10 ( negative value is not possible)
y = 5
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