Question

The difference of two numbers is 5 and their quotient is 4/9. Find the numbers. .​

Answer 1

let the numbers be x and y

Then,

x-y=5 first equation

x/y=4/9 second equation

=)9x=4y

=)x=4y/9

now putting value of x in first equation

(4y/9)-y=5

-5y/9=5

-5y=45

y=-9

x=4y/9

x=4×(-9)/9

x=4×-1

x=-4

Answer 2

The numbers are -4 and -9.

Step-by-step explanation:

Let one number is x and other number is y.

Given:

The difference of two numbers is 5 and their quotient is 4/9.

$= > \: x - y = 5$

And

$= > \: \frac{x}{y} = \frac{4}{9}$

$= > \: x = \frac{4y}{9}$

Now put the value of x in difference equation,

$= > \: \frac{4y}{9} - y = 5$

$= > \: \frac{4y - 9y}{9} = 5$

$= > \: \frac{ - 5y}{9} = 5$

$= > \: y = - 9$

Now,putting value of y in x equation

$= > \: x = \frac{4 \times - 9}{9}$

$= > \: x = - 4$

The numbers are -4 and -9.