the difference of two positive number is 12. if the new number formed by reversing the digits is greater than the original number by 18 find the original number. and check your answer
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let 1st no. =x
2nd no.=y
original no.=10x+y
reversed no.=10y+x
eq(1)
x+y=12
x=12-y
eq(2)
10y+x=10x+y+18
10y-y+x-10x=18
9y-9x=18
9y-9(12-y)=18 (putting x=12-y)
9y+9y=18+108
18y=126
y=126÷18
y=7
putting y=7 in eq 1st
x=12-7
x=5
original no.=10x+y
=10×5+7
=57
2nd no.=y
original no.=10x+y
reversed no.=10y+x
eq(1)
x+y=12
x=12-y
eq(2)
10y+x=10x+y+18
10y-y+x-10x=18
9y-9x=18
9y-9(12-y)=18 (putting x=12-y)
9y+9y=18+108
18y=126
y=126÷18
y=7
putting y=7 in eq 1st
x=12-7
x=5
original no.=10x+y
=10×5+7
=57
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