Question

The difference of two positive numbers is 72 and the quotient obtained on dividing the one by another is 4.Find the numbers?

Answer 1

Answer:

the numbers is 96,24

Step-by-step explanation:

let us assume the two positive numbers x and y

ATQ

x-y=72 (equation 1)

x/y=4

x=4y

substitute x value in equation 1

4y-y=72

3y=72

y=24

substitute y in equation 1 then

x-24=72

x=96

Answer 2

• Let two positive numbers be M and N.

》 Difference of two positive numbers is 72.

According to question,

=> M - N = 72

=> M = 72 + N __________ (eq 1)

》 The quotient obtained on dividing the one by another is 4.

We know that ..

Dividend = Divisor × Quotient + Remainder

Here..

• Divisor = N

• Quotient = 4

• Dividend = M

• Remainder = 0

=> M = (N × 4) + 0

=> M = 4N + 0

=> M = 4N _________ (eq 2)

Put value of M in (eq 1)

=> 4N = 72 + N

=> 4N - N = 72

=> 3N = 72

=> N = 24

Put value of N in (eq 2)

=> M = 4(24)

=> M = 96

_____________________________

Two positive numbers are 96 and 24.

______________ [ ANSWER ]

_____________________________

☆ VERIFICATION :

From above calculations we have M = 96 and N = 24

Put value of M and N in this : M - N = 72

=> 96 - 24 = 72

=> 72 = 72

______________________________