Question

The differential equation of the orthogonal
trajectories of the family of curves
xy=a? where a is the parameter mcq
​

Answer 1

Answer:

Given curve is xy = c2 x(dy/dx) + y = 0 (dy/dx) = -(y/x) Replacing dy/dx by – dx/dy, we get -dx/dy = –y/x xdx – ydy = 0 2xdx – 2ydy = 0 Integrating, we get x2 – y2 = a2 which is the required orthogonal trajectories.Read more on Sarthaks.com - https://www.sarthaks.com/563793/find-the-orthogonal-trajectories-of-the-family-of-rectangular-hyperbola-xy-c-2

plz mark branlies

Answer 2

help help help help plz plz