the differnce between the compound interest and the simple interest on a certain sum for 2 years at6% per annum is rs90 find the sum.
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t= 2years
r=6%
cp-si=90
then ....
cp-si=p(1+r/100)^t
90=p(1+6/100)^2
90/p= 106/100×106/100
90×100×100/106×106=p
r=6%
cp-si=90
then ....
cp-si=p(1+r/100)^t
90=p(1+6/100)^2
90/p= 106/100×106/100
90×100×100/106×106=p
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