the diffrence of two number 3 and their multipication is 504 then numbers are
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Let one number be x then other is x + 3
We are given, (x)(x+3) = 504
so, x² + 3x - 504 = 0
= x² + 24x - 21x - 504 = 0
= x(x+24) -21(x+24) = 0
so, x = 21 or x = -24
Hence Numbers are 21 and 24
We are given, (x)(x+3) = 504
so, x² + 3x - 504 = 0
= x² + 24x - 21x - 504 = 0
= x(x+24) -21(x+24) = 0
so, x = 21 or x = -24
Hence Numbers are 21 and 24
armandogra:
thank u sir
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see this... the nos are 24 and 21
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