The digit at ten'place of a two digit no. Is four times the digit at unit's place.If the sum of this number and the number formed by reversing the digits is 55.Find the number.
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Let the digit at one's place be x.
The digit at ten's place=4x
Therefore, the two digit number=10(4x) +x=40x+x=41x
On reversing the number,the digit at one's place =x
And the digit at ten's place=4x
So, the two digit no.=10(x)+4x
=10x+4x=14x
=According to the question,
=41x+14x=55
=55x=55
=x=55/55
=x=1
The two digit number=41x=41*1=41
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