The digit at ten’s place of a two digit number is greater than the square of digit at unit’s place (x) by 5 and the number formed is 61.
Answers
Given : The digit at ten’s place of a two digit number is greater than the square of digit at unit’s place by 5
To Find : the number formed
Solution:
Let say two Digit number is
AB
1 ≤ A ≤ 9 ( As number is two digit hence A can not be zero)
0 ≤ B ≤ 9
The digit at ten’s place of a two digit number is greater than the square of digit at unit’s place by 5
A = B² + 5
B = 0 => A = 5 Number = 50
B = 1 => A = 6 Number = 61
B = 2 => A = 9 Number = 92
B = 3 => A = 14 > 9 Hence not possible
So possible numbers are
50
61
92
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