Math, asked by poorvapandey433, 8 months ago

the digit at tens place of a two digit number is greater than the square of digit at the unit place X by 5 and number formed is 61​

Answers

Answered by amitnrw
1

Given : The digit at ten’s place of a two digit number is greater than the square of digit at unit’s place  by 5

To Find :  the number formed

Solution:

Let say two  Digit number is

AB

1 ≤ A ≤ 9  ( As number is two digit hence A can not be zero)

0 ≤ B ≤ 9

The digit at ten’s place of a two digit number is greater than the square of digit at unit’s place by 5

A =  B² + 5

B = 0  => A = 5   Number = 50

B = 1   => A  = 6  Number = 61

B = 2  => A = 9   Number = 92

B = 3 => A = 14  > 9 Hence not possible

So possible numbers are

50

61

92

Learn More:

a two digit number is 6 times the sum of its digits. the tens digit is 1 ...

https://brainly.in/question/8019099

In a two digit number ,theone digit is 3 times the ten's digit.if 10 is ...

https://brainly.in/question/7626016

Similar questions