Question

The digit at tens place of a two digit number is twice the digit at the units place. if the sum pf the number and the number formed by reversing its digits is 66, find the number.

Answer 1

let the digit at tenth place be x and digit at ones place be y.

ATQ  x=2y

10x+y+10y+x=66

11x+11y=66

x+y=6

2y+y=6

3y=6

y=2

putting value of y in 1

x=2y

x=2×2

x=4

number is 42