Question

The digit at the ones place is double the digit in the tens place of a two digit number. if the number exceeds by 18 the sum of the digit, find the number​

Answer 1

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: Question :- \: \star}}}}}$

The digit at the ones place is double the digit in the tens place of a two digit number. if the number exceeds by 18 the sum of the digit, find the number.

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$\underline{\boxed{\textsf{Number = {\textbf{24 }}}}} \qquad\qquad \bigg\lgroup\bold{Correct \ Answer} \bigg\rgroup$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

The digit at ones place = 2x

The number at tens place be x.

$\Large{\underline{\underline{\bf{Find:-}}}}$

Find the Two digit number .

$\Large{\underline{\underline{\bf{Solution:-}}}}$

As according to the given :-

So, we consider

the number at tens place be X

let the number at one's place be 2x

Now ,

The number together will be 10 x + 1(2x) = 12x

 So , as we know the number exceeds the digits sum by 18.  

Now, Sum of the digits = x + 2x = 3x

As per the question :--

$:\implies\purple{\tt{12x = 3x + 18}}$

✦ 12x - 3x = 18

✦ 9x = 18

$\therefore\underline{\boxed{\textsf{ x = {\textbf{2}}}}} \qquad\qquad \bigg\lgroup\bold{the \ number \ at \ tens' place} \bigg\rgroup$

From this :-

The digit at ones place = 2x

The digit at ones place = 2 × 2 = 4

The number at tens place is x = 2

Hence ,

The no is 10 x + (2x)

= 10 × 2 + ( 2 × 2 )

= 20 + 4

= 24 is the number .